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leetcode-1 solution finished
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source/_posts/leetcode-1-two-sum-md.md
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---
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title: leetcode-1-two-sum
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tags: ["leetcode"]
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date: 2019-11-24 21:06:37
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---
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> 嗯,虽然以前就就在Leetcode上面刷过题,但是都没有坚持下去。这次准备重操旧业,希望能起码做到一天一道题吧。
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首先是A+B问题,按理说是所有题目的开始。但是很遗憾的是我还是提交了三次才AC,感觉自己弱爆了。废话不多说,进入正题。
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<!--more-->
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```
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1. Two Sum
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Given an array of integers, return indices of the two numbers such that they add up to a specific target.
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You may assume that each input would have exactly one solution, and you may not use the same element twice.
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Example:
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Given nums = [2, 7, 11, 15], target = 9,
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Because nums[0] + nums[1] = 2 + 7 = 9,
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return [0, 1].
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```
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题意很简单,就是给一个list,然后给定一个target,需要从list中找到两个数的和是target,然后输出这两个数的下标。需要注意的是每个元素只能用一次。
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我很快就完成了,但是第一版代码是错的,代码如:
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```python3
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class Solution:
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def twoSum(self, nums: List[int], target: int) -> List[int]:
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m = dict()
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for i in range(len(nums)):
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if i not in m:
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m[nums[i]] = i
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if nums[i] in m and target-nums[i] in m:
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return [m[nums[i]], m[target - nums[i]]]
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return []
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```
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致命的问题在于如果test case是[3,2,1] 6,那么输出是 [0,0],也就是说第一个元素用了两次,嗯,这么简单的边界都翻车。
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然后很快又改好了,加了判断条件,代码如:
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```python3
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class Solution:
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def twoSum(self, nums: List[int], target: int) -> List[int]:
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m = dict()
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for i in range(len(nums)):
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if nums[i] not in m:
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m[nums[i]] = i
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if nums[i] in m and target-nums[i] in m and m[nums[i]] != m[target - nums[i]]:
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return [m[nums[i]], m[target - nums[i]]]
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return []
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```
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然后又WA了。。。嗯,仔细分析了一下,发现test case是[3,3] 6的时候,输出是空。嗯,分支条件写错了。不应该判断两个数字都在字典里面,因为如果有两个相同的元素的话只有一个会加入到字典中。为了解决这个问题,嗯,直接换个写法就好,如:
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```python3
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class Solution:
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def twoSum(self, nums: List[int], target: int) -> List[int]:
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m = dict()
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for i in range(len(nums)):
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if nums[i] not in m:
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m[nums[i]] = i
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if target-nums[i] in m and i != m[target - nums[i]]:
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return [i, m[target - nums[i]]]
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```
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嗯,总算AC了。我感觉每天一题的目标估计是要GG了。
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# Refer
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[1. Two Sum](https://leetcode.com/problems/two-sum/)
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# Appendix
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@@ -43,6 +43,7 @@ Gohugo是个非常高效的静态博客生成器,而且是用我当时最痴
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[Makefile git add commit push github All in One command](https://medium.com/@panjeh/makefile-git-add-commit-push-github-all-in-one-command-9dcf76220f48)
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[Cross-reference (named anchor) in markdown](https://stackoverflow.com/questions/5319754/cross-reference-named-anchor-in-markdown)
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# Appendix
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## Makefile
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@@ -8,4 +8,4 @@
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> 面向阳光,做一个开朗自信的人。
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你好👋我的名字是d0zingcat,目前就职于[莉莉丝游戏](https://www.lilithgames.com/cn/?nlr=1),是个搬砖的码农,欢迎小伙伴拿简历来砸我。我会使用Python,Golang,Erlang进行编程,目前沉醉于Elixir无法自拔,也有计划学习一下Rust、Lua、Js。也许在未来的某天我会试着更新这个"关于我"页面。
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你好👋我的名字是d0zingcat,目前就职于[莉莉丝游戏](https://www.lilithgames.com/cn/?nlr=1),是个搬砖的码农,欢迎小伙伴拿简历来砸我。我会使用Python,Golang,Erlang, Elixir, Bash Shell 进行编程,也有计划学习一下Rust、Lua、JS。也许在未来的某天我会试着更新这个"关于我"页面。
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